(x^2-x-5)(2x+3)=0

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Solution for (x^2-x-5)(2x+3)=0 equation: 


Simplifying
(x2 + -1x + -5)(2x + 3) = 0

Reorder the terms:
(-5 + -1x + x2)(2x + 3) = 0

Reorder the terms:
(-5 + -1x + x2)(3 + 2x) = 0

Multiply (-5 + -1x + x2) * (3 + 2x)
(-5(3 + 2x) + -1x * (3 + 2x) + x2(3 + 2x)) = 0
((3 * -5 + 2x * -5) + -1x * (3 + 2x) + x2(3 + 2x)) = 0
((-15 + -10x) + -1x * (3 + 2x) + x2(3 + 2x)) = 0
(-15 + -10x + (3 * -1x + 2x * -1x) + x2(3 + 2x)) = 0
(-15 + -10x + (-3x + -2x2) + x2(3 + 2x)) = 0
(-15 + -10x + -3x + -2x2 + (3 * x2 + 2x * x2)) = 0
(-15 + -10x + -3x + -2x2 + (3x2 + 2x3)) = 0

Combine like terms: -10x + -3x = -13x
(-15 + -13x + -2x2 + 3x2 + 2x3) = 0

Combine like terms: -2x2 + 3x2 = 1x2
(-15 + -13x + 1x2 + 2x3) = 0

Solving
-15 + -13x + 1x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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